TCS NQT• Prep
Strong Number Check
Here is the optimized solution in Java. Copy or view it below.
Java
package Problems_On_Number;
import java.util.Scanner;
/*
* When the sum of factorial of individual digits of a number is equal to the original number
* the number is called a strong number.
*/
public class StrongNumberCheck {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter the number:");
int n = sc.nextInt();
int sum = 0;
int dummy = n;
while (n > 0) {
int temp = n % 10;
sum += fact(temp);
n /= 10;
}
if (sum == dummy)
System.out.println("it is a strong number.");
else
System.out.println("it is not a strong number." + sum);
sc.close();
}
public static int fact(int i) {
if (i == 0) {
return 1;
}
return i * fact(i - 1);
}
}