TCS• Prep
Merge Sort
Here is the optimized solution in Java. Copy or view it below.
Java
package Problems_On_Sorting;
import java.util.Scanner;
public class MergeSort {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the size of the Array:");
int n = sc.nextInt();
int[] arr = new int[n];
for (int i = 0; i < n; i++) {
System.out.println("enter the " + (i + 1) + " element of the array");
arr[i] = sc.nextInt();
}
int l = 0;
int r = n - 1;
mergesort(arr, l, r);
System.out.println("the sorted array using Merge sort is:");
for (int i = 0; i < n; i++) {
System.out.print(arr[i] + " ");
}
sc.close();
}
public static void mergesort(int[] arr, int l, int r) {
if (l < r) {
int mid = (l + r) / 2;
mergesort(arr, l, mid);
mergesort(arr, mid + 1, r);
merge(arr, l, mid, r);
}
}
public static void merge(int[] arr, int l, int mid, int r) {
int i = l;
int j = mid + 1;
int k = 0;
int[] b = new int[r - l + 1];
while (i <= mid && j <= r) {
if (arr[i] < arr[j]) {
b[k] = arr[i];
i++;
} else {
b[k] = arr[j];
j++;
}
k++;
}
while (i <= mid) {
b[k] = arr[i];
i++;
k++;
}
while (j <= r) {
b[k] = arr[j];
j++;
k++;
}
for (k = 0; k < b.length; k++) {
arr[l + k] = b[k];
}
}
}