Here is the optimized solution in Java. Copy or view it below.
Java
package Problems_On_Number;
import java.util.Scanner;
public class PerfectNumberCheck {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter the number:");
int n = sc.nextInt();
int sum = 0;
for (int i = 1; i < n; i++) {
if (n % i == 0) {
sum += i;
}
}
if (sum == n)
System.out.println("it is a perfect number");
else
System.out.println("it is not a perfect number as the sum of its factors is " + sum);
sc.close();
}
}