Here is the optimized solution in Java. Copy or view it below.
Java
package Problems_On_Number;
import java.util.Scanner;
public class LeapYearCheck {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter the Year:");
int n = sc.nextInt();
if (n % 400 == 0 || (n % 4 == 0 && n % 100 != 0)) {
System.out.println("it is a Leap Year");
} else
System.out.println("it is not leap year");
sc.close();
}
}