Here is the optimized solution in Java. Copy or view it below.
Java
package Problems_On_Number_System;
import java.util.Scanner;
public class DecimalToBinary {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter the Decimal value:");
int n = sc.nextInt();
String s = "";
while (n > 0) {
int remainder = n % 2;
s = remainder + s;
n = n / 2;
}
System.out.println("the binary value is " + s);
sc.close();
}
}